Given: The vertices of ∆ABC are A (1, 4), B (− 3, 2) and C (− 5, − 3).
To find: The equations of the altitudes of a ΔABC whose vertices are A (1, 4), B (-3, 2) and C (-5, -3).
Explanation:
Diagram:
Hence,
Equation of CF is: y + 3 = -2(x + 5)
⇒ 2x + y + 13 = 0
Equation of AD is: y – 4 = \(-\frac{2}{5}\) (x – 1)
⇒ 2x + 5y – 22 = 0
Equation of BE is: y – 2 = \(-\frac{6}{7}\) (x + 3)
⇒ 6x + 7y + 4 = 0
