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If equation of the line passing through (1, 5) and perpendicular to the line 3x – 5y + 7 = 0 is 

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If equation of the line passing through (1, 5) and perpendicular to the line 3x – 5y + 7 = 0 is 

A. 5x + 3y – 20 = 0 

B. 3x – 5y + 7 = 0 

C. 3x – 5y + 6 = 0 

D. none of these

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1 Answer

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A line perpendicular to 3x − 5y + 7 = 0 is given by 

5x + 3y + λ = 0 

This line passes through (1, 5). 

5 + 15 + λ = 0 

⇒ λ = – 20 

Therefore, the equation of the required line is 5x + 3y – 20 = 0

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