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Evaluate the following limit : \(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \)

lim(x→0) (tan 8x)/(sin 2x)

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To find: \(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \)

\(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \)

Multiplying and Dividing by 8x in numerator & Multiplying and Dividing by 2x in the denominator:

As, x → 0 ⇒ 8x → 0 & 2x → 0

Now, put 2x = y and 8x = t

Formula used:

= 4

Hence, the value of \(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \) = 4

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