To find: \(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \)
\(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \)
Multiplying and Dividing by 8x in numerator & Multiplying and Dividing by 2x in the denominator:

As, x → 0 ⇒ 8x → 0 & 2x → 0

Now, put 2x = y and 8x = t

Formula used:

= 4
Hence, the value of \(\lim\limits_{\text x \to 0}\cfrac{tan\,8\text x}{sin\,2\text x} \) = 4