Question

If a, b, c are in G.P. and a^1/x = b^1/y = c^1/z, then xyz are in

A. AP

B. GP

C. HP

D. none of these

Answer 1

Given: a,b,c are in GP

Let us assume

As a,b,c, are in GP

b² = ac

⇒ k^2y = k^x.k^z

= k^x+z

⇒ 2y = x+z

∴ x,y,z are in AP