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If a, b, c are in G.P. and a1/x = b1/y = c1/z, then xyz are in 

A. AP 

B. GP 

C. HP 

D. none of these

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1 Answer

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edited by

Correct answer is A. AP

Given: 

a,b,c are in GP 

Let us assume 

As a,b,c, are in GP b 2 =ac 

⇒ k 2y =kx .kz 

=kx+z 

⇒ 2y = x+z

∴ x,y,z are in AP

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