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Let x be the A.M. and y, z be two G.M.s between two positive numbers. Then, y3+z3/xyz is equal to

A. 1

B. 2

C. 1/2

D. none of these

1 Answer

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Best answer

Let the numbers be a,b.

a,x,b = 2x = a+b

a,y,z,b = y2 = az ; z2 = by [a,b,c GM = b2 = ac]

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