Question

A force of 8 N is applied to a body at a distance of 20 cm from the point at which it is pivoted. Calculate the torque or moment of force about the pivot.

Answer 1

Given, applied force, f = 8 N.
Distance of the point of application of force from the axis of rotation, `r = 20 cm = (20)/(100)m`
Hence, Torque `(tau) = F xx r`
` = 8 N xx (20)/(100)m`
` = 1.6 N` m