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If `"cosec"theta=2`, show that `(cottheta+(sintheta)/(1+costheta))=2`.

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`"cosec"theta =2 implies sin theta =(1)/(2) =(BC)/(AC).`
`AB^(2)=AC^(2)-BC^(2)=(2)^(2)-(1)^(2)=4-1=3implies AB =sqrt(3).`
Given expression `={sqrt(3)+(1)/((2+sqrt(3)))xx((2-sqrt(3)))/((2-sqrt(3)))}=2.`
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