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If `tantheta=(20)/(21)` , show that `(1-sintheta+costheta)/(1+sintheta+costheta)=3/7`

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If `tantheta=(20)/(21)` , show that `(1-sintheta+costheta)/(1+sintheta+costheta)=3/7`
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`tan theta =(20)/(21)=(BC)/(AB).`
` therefore AC^(2)=AB^(2) +BC^(2)=(21)^(2)+(20)^(2)=441+400=841`
`implies AC=sqrt(841)=29.`
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