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If `sec theta =(5)/(4),"show that "((2cos theta - sin theta ))/((cot theta - tan theta ))=(12)/(7).`

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`Sectheta =(5)/(4)implies cos theta =(4)/(5)=(AB)/(AC).`
`therefore BC^(2)=AC^(2)-AB^(2)=(5)^(2)-(4)^(2)=25-16=9implies BC=3.`
`sin theta =(3)/(5), cos theta =(4)/(5), tan theta =(3)/(4) , cot theta =(4)/(3).`
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