Find the particular solution of the differential equation log (dy/dx) = 3x + 4y, given that y = 0 when x = 0. ​

Question

Find the particular solution of the differential equation log \((\frac{dy}{dx})\) = 3x + 4y, given that y = 0 when x = 0.

Answer 1

log \((\frac{dy}{dx})\) = 3x + 4y

⇒ y = 0

⇒ x = 0

⇒ For y = 0, x = 0, we have

Hence, the particular solution is:

⇒ 4e^3x + 3e^-4x = 7