Find the general solution of the following differential equation: dy/dx = 1 - cos x/1 + cos x ​

Question

Find the general solution of the following differential equation:

\(\frac{dy}{dx}\) = \(\frac{1-cosx}{1+cosx}\)

dy/dx = 1 - cos x/1 + cos x

Answer 1

 \(\frac{dy}{dx}\) = \(\frac{1-cosx}{1+cosx}\)

dy = \(\frac{1-cosx}{1+cosx}dx\)

cos x can be written as cos x = \(\frac{1-tan^2(\frac{x}{2})}{1+tan^2(\frac{x}{2})}\)

Integrating on both the sides,