Given : Let u = tan-1\(\left(\cfrac{\text x}{\sqrt{1-\text x^2}}\right)\)and v = cos-1(2x2 - 1).
tan-1(x/√(1 - x2))
To differentiate : tan-1\(\cfrac{\text x}{\sqrt{1-\text x^2}}\) with respect to cos-1(2x2 - 1)
Formula used :


The CHAIN RULE states that the derivative of f(g(x)) is f’(g(x)).g’(x)

Let u = tan-1\(\cfrac{\text x}{\sqrt{1-\text x^2}}\) and v = cos-1(2x2 - 1)
Differentiating u with respect to x

Differentiating v with respect to x
