Answer :
1. Answer : (b) complex salt
Explanation: Potassium ferrocyanide is the inorganic compound with formula K4[Fe(CN)6]·3H2O. It is the potassium salt of the coordination complex [Fe(CN)6]4−. This salt forms lemon-yellow monoclinic crystals.
2. Answer : (a) Primary valency is ionisable
Explanation: Primary valency is ionisable according to Werner's theory of coordination compounds.
According to Werner's coordination theory, there are two kinds of valency, primary and secondary. The primary valency of a central metal ion is satisfied with anions.
3. Answer : (c) tetradentate
Explanation: Number of donor atoms in N(CH2CH2NH2)3 is four hence it is a tetradentate ligand.
4. Answer : (b) Oxalate
Explanation: In chelation, ring formation occurs because two atoms from the same ligand coordinate with the metal atom. This cannot happen if the ligand is monodentate.
Oxalate is a bidentate ligand hence it forms a chelate. It can coordinate with both of its negatively charged O atoms. Acetate, cyanide and ammonia are monodentate ligands. They do not form chelates.

5. Answer : (c) ONO
Explanation: Neutral ligand means ligand with no charge on it. Example: HO, NH3, CO, C2H4. ONO− has charge on it, therefore it is not neutral ligand.
6. Answer : (d) SCN–
Explanation: SCN- is a monodentate ligand hence cannot show chelation.
7. Answer : (d) [Co(NH3)3Cl3]
Explanation: Optical isomerism is exhibited by only those complexes which lack elements of symmetry. [Co(NH3)3Cl3] shows facial as well as meridional isomerism. But both the forms contain plane of symmetry. Thus, this complex does not exhibit optical isomerism.
8. Answer : (c) 3
Explanation: For the square planar complex [Mabcd] where M is the central atom and a,b,c,d are monodentate ligands, the number of possible geometrical isomers are three. In isomer I, C is opposite to A. In isomer II, D is opposite to A. In isomer III, B is opposite to A.

9. Answer : (d) d2sp3
Explanation: It involves sp3d2 hybridization.
10. Answer : (a) 0
Explanation: Due to the presence of strong ligand, all the electrons get paired. So the number of unpaired electrons is 0.
11. Answer : (a) the formation of complex ion
Explanation: When mercuric iodide is dissolved in KI solution, it shows optical activity due to the complex formation. A complex called Nessler's reagent is formed.
12. Answer : (b) disodium salt of EDTA
Explanation: The hardness of water is estimated by simple titration of ethylene diamine tetraacetate (EDTA) solution. EDTA forms stable complexes with the metal ions present in the hard water since stability constants of calcium and magnesium complexes of EDTA are different, even the selective estimation of these ions is possible.
13. Answer : (a) cis-platin
Explanation: The chemical formula of Grignard reagent is R−MgX where Mg is a metal and R is any organic group. Hence, it is an organometallic compound. Therefore, the correct option is option B because cis-platin does not obey the criteria to be called an organometallic compound.
14. Answer : (a) primary valency is ionizable
Explanation: According to Werner theory for co-ordination compounds primary valency are ionizable.
15. Answer : (c) [CrCl2(H2O)4] Cl . 2H2O
Explanation: As 1/3 of total chlorine of the compound is precipitated by adding AgNO3 to its aqueous solution so only one chloride ion is available for ionization, so compound is [CrCl2(H2O)4] Cl.2H2O.
16. Answer : (c) the number of ligands around a metal ion bonded by sigma bonds
Explanation: The number of atoms of the ligands that are directly bound to the central metal atom or ion by coordinate bonds is known as the coordination number of the metal atom or ion. Co-ordination number of metal = number of \(\sigma\)bonds formed by metal with ligands.
17. Answer : (d) hexadentate ligand
Explanation: [EDTA]4- forms very stable complexes with most of the transition metals. This hexadentate ligand forms very stable complexes (usually octahedral structures) with most of the transition metals. The donor atoms in [EDTA]4- are the two N atoms, and the four, negatively charged O atoms.
18. Answer : (b) 6
Explanation: Co- ordination number of Ni in [Ni(C2O4)3]4– is 6. This is because C2O2−4 (oxalate) is a bidentate ligand and thus, each coordinated with the central atom at two sites.
19. Answer : (b) basic in nature
Explanation: The ligands are basic in nature. They donate their lone pair of electrons to the central metal atom and form a coordinate bond.
20. Answer : (d) Thiocyanato
Explanation: Ambidentate ligand is a type of ligand which have the ability to bind to the central atom via the atoms of two different elements. Examples: thiocyanate ion(NCS–) which can bind to the central metal atom or ion with either nitrogen or sulphur atoms.
21. Answer : (c) Bridging ligand
Explanation: It is a bidentate ligand having two NH donating groups . when both the lone pair of electrons are donating to metal atom then it behaves as bridging ligand. cobalt, nickel and zinc form complexes in which NH2 -NH2 acts as bridging ligand.
22. Answer : (b) NH4
Explanation: In ammonia, N atom has one lone pair of electrons. Nitrogen donates this lone pair of electrons to proton to form ammonium ion. So NH4+ ion does not have a lone pair of electrons which it can donate to central metal ion. Hence it cannot behave as a ligand.
23. Answer : (b) Linkage isomers
Explanation: The complex [Co(NH3)5(NO2)]2+ and [Co(NH3)5 (ONO)]2+ are called linkage isomers due to presence of NO2 ligand.
24. Answer : (b) Hexadentate
Explanation: EDTA is a multidentate ligand. Its denticity (multiplicity) is 6. In EDTA, there are four Oxygen atoms and two Nitrogen atoms.
25. Answer : (b) Grignard's reagent
Explanation: An example of a sigma bonded organometallic compound is Grignard's reagent. Whereas, ruthenocene, ferrocene and cobaltocene are not sigma bonded organometallic compound.
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