Correct option is (b) 92 Hz, 184 Hz
Let, frequency of 1st fork = v
frequency of 2nd fork = v + 4
So, frequency of 24th fork = v + 23 x 4
But frequency of last is the octave of 1st,
\(\therefore\) 2v = v + (23 x 4)
⇒ v = 92 Hz
Frequency of last fork = 2v = 184 Hz