∫ x tan^-1 x dx = ?

Question

Mark (√) against the correct answer of the following:

∫ x tan^-1 x dx = ?

A. \(\frac{1}{2}\)(x² + 1) tan^-1 x - \(\frac{1}{2}\)x + C

B. \(\frac{1}{2}\)(x² - 1) tan^-1 x - \(\frac{1}{2}\)x + C

C. \(\frac{1}{2}\)(x² + 1) tan^-1 x + \(\frac{1}{2}\)x + C

D. None of these

Answer 1

Correct answer is A.

To find: Value of ∫ x tan^-1 x dx

Formula used:

Taking 1^st function as tan^-1 and second function as x