Mark (√) against the correct answer of the following:
∫ x tan-1 x dx = ?
A. \(\frac{1}{2}\)(x2 + 1) tan-1 x - \(\frac{1}{2}\)x + C
B. \(\frac{1}{2}\)(x2 - 1) tan-1 x - \(\frac{1}{2}\)x + C
C. \(\frac{1}{2}\)(x2 + 1) tan-1 x + \(\frac{1}{2}\)x + C
D. None of these