Question

The oxidation state of S - atoms in S₄O₆^2- from left to right respectively are

(a) + 3, + 1, + 1, + 3

(b) + 4, + 1, + 1, + 4

(c) + 5, 0, 0, + 5

(d) + 6, 0, 0, + 6

Answer 1

Answer is : (c) + 5, 0, 0, + 5

For corner S - atom, +2 each from (= O), +1 from (O^-) and zero from - S. Therefore, its oxidation number is +5. Middle S - atoms has zero oxidation number.