Given: Density (d) = 7.29 g cm-3 , Edge length (a) = 289 pm = 289 \(\times\)10–12 m = 289 \(\times\)10-10 cm
Atomic mass = 52 a.m.u.
To find: Type of unit cell

\(\therefore\) Type of crystal lattice = bcc
Ans: Since the given unit cell contains 2 atoms, it has a body centred cubic (bcc) structure.