Question

An element crystallizes in bcc structure. The edge length of its unit cell is 288 pm. If the density of the crystal is 7.2 g cm^-3 , what is the atomic mass of the element?

Answer 1

Given: Edge length (a) = 288 pm = 288 \(\times\) 10^–12 m = 288 \(\times\)10^-10 cm, Density (d) = 7.2 g cm^-3 

To find: Atomic mass

Ans: The atomic mass of the given element is 51.8 a.m.u.