Question

An element has a body centred cubic (bcc) structure with a cell edge of 288 pm. The density of element is 7.2 g cm^–3. How many atoms are present in 208 g of this element?

Answer 1

Given: Density (d) = 7.2 g cm^-3 , Edge length (a) = 288 pm = 288 \(\times\) 10^–12 m = 288 \(\times\) 10^-10 cm. Mass of the element = 208 g

To find: Number of atoms present in 208 g of the element

Ans: Number of atoms present in 208 g of the given element is 2.419\(\times\)10²⁴ atoms.