Question

An element has bcc structure with a cell edge of 288 pm. the density of the element is 7.2 gcm^-3 . How many atoms are present in 208 g of the element.

Answer 1

An elemeñt has bec structure with a cell edge of 288 pm. The density of the element is 7.2 gcm^-3 . 

For the Bec structure, n = 2

By mole concept, 51.42 g of the element contain 6023 x 10²³ atom 208 g of the element will contain

= \(\frac{6.023\times10^{23}\times208}{51.42}\) atoms = 24.17 x 10²³ atoms (or) 2.417 x 10²⁴ atoms