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~(p ∨ ~q) is equal to 

(A) ~p ∨ q 

(B) ~p ∧ q 

(C) ~p ∨ ~p 

(D) ~p ∧ ~q

1 Answer

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Best answer

Correct option: (B) ~p ∧ q 

~[p ∧ (~q)] ≡ ~p ∧ ~(~q) ≡ ~p ∧ q

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