Correct option: (D) 16 g of CH4
18 g of H2O ≡ 1 mole = 3 x NA atoms
(∴ Number of atoms = n x NA x Atomicity)
16 g of O2 ≡ \(\cfrac{1}{2}\) mole = 2 x \(\cfrac{1}{2}\) NA atoms
4.4 g of CO2 ≡ \(\cfrac{1}{10}\) mole ≡ 3 x \(\cfrac{1}{10}\) x NA atoms
16 g of CH4 ≡ 1 mole = 5 x NA atoms
∴ maximum number of atoms is present in 16 g of CH4.
