Question

The horizontal component of earth’s magnetic field at a given place is 0.4 × 10^–4 Wb/m² and angle of dip is 30°. Calculate the value of

(i) Vertical component

(ii) Total intensity of earth’s magnetic field.

Answer 1

i. Given H = 0.4 \(\times\) 10^-4 Wb/m² , \(\theta\) = 30\(^\circ\)

tan \(\theta\) \(\Rightarrow\) \(\cfrac{V}{H}\) \(\Rightarrow\)vertical component

V = H  tan \(\theta\) = 0.4 \(\times\) 10^-4 \(\times\) tan 30^{\(^\circ\)}

^{\(\cfrac{0.4 \times 10^{-4}}{\sqrt{3}} = 0.23\times 10^{-4}\,Wb/m^2\)}

ii. Total intensity of earth's magnetic field