Horizontal component of earth’s magnetic field at a place is √ times its vertical component. What is the value of angle of d

Given H = \(\sqrt{3}V\,\Rightarrow tan\,\theta=\cfrac{V}{H}=\cfrac{1}{\sqrt{3}}\)

\(\Rightarrow\) Angle of dip, \(\theta\) = tan^-1\(\left(\cfrac{1}{\sqrt{3}}\right)=30^\circ\)

Horizontal component of earth’s magnetic field at a place is √ times its vertical component. What is the value of angle of dip at that place?