Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
106 views
in Mathematics by (71.9k points)
closed by
8 wooden rectangular parallelopiped of same shape when arranged one over another, the volume becomes 128 cc. If the base of each rectangular parallelopipcd be a square and of height 1 cm, then find the length, breadth and height of each wooden rectangular parallelopiped.

1 Answer

0 votes
by (72.1k points)
selected by
 
Best answer
Let the length and breadth of each wooden rectangular parallelopiped be x cm. Since · there are 8 such parallelopiped of height 1 cm each have been arranged one over another, the total height . of this soild object is 8 cm. ·
So, the volume of whole solid objecti `= x xx x xx 8 " cc" = 8x^2` cc
As per question `8x^2=128 or , x^2 = 128/8 = 16 or, x sqrt(16) ` or , x =4
Hence the length, breadth and height of each of the cuboidal solid are 4 cm, 4 cm and l cm respectively.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...