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साबित करें कि
`(sinA+sin2A+sin4A+sin5A)/(cosA+cos2A+cos4A+cos5A)=tan3A`

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बायाँ पक्ष `=((sin5A+sinA)+(sin4A+sin2A))/((cos5A+cosA)+(cos4A+cos2A))`
`=(2sin3Acos2A+2sin2A+2sin3AcosA)/(2cos3Acos2A+2cos3AcosA)`
`=(2sin3A(cos 2A+cosA))/(2cos3A(cos2A=cosA))=tan3A`

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