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सिद्ध कीजिए कि `(cos4A+cos3A+cos2A)/(sin4A+sin3A+sin2A)=cot3A`

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बायाँ पक्ष `(cos4A+cos3A+cos2A)/(sin4A+sin3A+sin2A)=((cos4A+cos2A)+cos 3A)/((sin 4A+sin 2A)+sin 3A)`
`=(2cos((4A+2A)/(2))cos((4A-2A)/(2))+cos 3A)/(2sin ((4A+2A)/(2))cos((4A-2A)/(2))+sin 3A)`
`=(2cos 3AcosA+cos 3A)/(2sin 3AcosA+sin 3A)=(cos 3A(2cos A+1))/(sin 3A(2cos A+1))`
`=(cos 3A)/(sin 3A)=cot 3A=` दायाँ पक्ष

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