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यदि `cos A+cosB=(1)/(3)` तथा `sinA+sinB=(1)/(4),` तो सिद्ध कीजिए कि `tan((A+B)/(2))=(3)/(4)`

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यदि `cos A+cosB=(1)/(3)` तथा `sinA+sinB=(1)/(4),` तो सिद्ध कीजिए कि `tan((A+B)/(2))=(3)/(4)`
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`cosA+cosB=(1)/(3)" "rArr 2 cos((A+B)/(2))cos((A-B)/(2))=(1)/(3)" …(1)"`
अब `sinA+sinB=(1)/(4)rArr 2sin((A+B)/(2))cos((A-B)/(2))=(1)/(4)" …(2)"`
समीकरण (1 ) से समीकरण (2 ) में भाग करने पर , सरल करते हुए
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