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Find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils.

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Total number of pens = 1001 

Total number pencils = 910 

∴ Maximum number of students who get the same number of pens and pencils = HCF (1001, 910) 

Prime factorization: 

1001 = 11 × 91 

910 = 10 × 91 

∴ HCF = 91 

Hence, 91 students receive same number of pens and pencils.

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