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When the frequency of light incident an a metallic plate is doubled , the KE of the emitted photoelectrons will be :

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When the frequency of light incident an a metallic plate is doubled , the KE of the emitted photoelectrons will be :
A. Doubled
B. Halved
C. Increased out more than doubled of the previous KE
D. Remains unchanged
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Correct Answer - C
`hv = hv_(0) +KE` threshold frequency of metal is constant
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