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When the frequency fo light incident an a metallic plate is doubled , the 1KE` of the emitted photoelectrons will be :
A. Double
B. Halved
C. Increased but more than doubled fo the previous KE
D. Unchanged

1 Answer

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Correct Answer - C
`hv_1` = work funciton ` + KE_1`
` 2 xx hv_1` = work function `+ KE_2`.

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