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The ionisation energy of H atom is `13.6 eV` The inoisation energy of `Li^(2+)` law will be

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The ionisation energy of H atom is `13.6 eV` The inoisation energy of `Li^(2+)` law will be
A. 54.4 eV
B. 122.4 eV
C. 13.6 eV
D. 27.2 eV
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Correct Answer - 122.4 eV
`E_(1) "for" Li^(2+) = E_(1) "for" H xx Z^(2)[ for Li,Z = 3] = 13.6 xx 9 = 122.4eV`
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