Question

`A + B hArrC + D`. If finally the concentrations of A an d B are both equal but at equilibrium concentration of D will be twice of that of A then what will be the equilibrium constant of reaction.
A. `4//9`
B. `9//4`
C. `1//9`
D. `4`

Answer 1

Correct Answer - D
`{:(A,+,B,hArr,C,+,D),(x,,x,,0,,0),(,,,,2x,,2x):}`
`K_(c) = ([C][D])/([A][B]) = (2x.2x)/(x.x) = 4`