Question

The rate constant for forward and backward reactions of hydrolysis of ester are `1.1xx10^(-2)` and `1.5xx10^(-3)` per minute respectively. Equilibrium constant for the reaction is
A. `4.33`
B. `5.33`
C. `6.33`
D. `7.33`

Answer 1

Correct Answer - D
`K_(f) = 1.1xx10^(-2), K_(b) = 1.5xx10^(-3)`
`K_(c) = (K_(f))/(K_(b)) = (1.1xx10^(-2))/(1.5xx10^(-3)) = 7.33`