Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
104 views
in Chemistry by (63.2k points)
closed by
`0.96 g` of `HI` were heated to attain equilibrium `2HIhArrH_(2)+I_(2)`. The reaction mixture on titration requires `15.7mL` of `N//10` hypo solution. Calculate degree of dissociation of `HI`.

1 Answer

0 votes
by (67.2k points)
selected by
 
Best answer
Correct Answer - `20.9%`
meq of `l_(2)=(W_(l_2))/(127)xx1000=1.57`
`W_(l_(2))=(127xx1.57)/(1000)` `n_(l_(2))=(1.57)/(2000)``2HI(g)harrH_(2)(g)+l_(2)(g)`
`a-aalpha , (aalpha)/(2) , (aalpha)/(2) , (0.96)/(256)xxalpha=(1.57)/(2000)`
`alpha=0.209`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...