Question

`15` mol of `H_(2)` and `5.2` moles of `I_(2)` are mixed and allowed to attain eqilibrium at `500^(@)C` At equilibrium, the concentration of HI is founf to be `10` mol. The equilibrium constant for the formation of HI is.
A. `50`
B. `25`
C. `200`
D. `15`

Answer 1

Correct Answer - A
`{:(,H_(2),+,I_(2),hArr,2HI),(t=0,15,,5.2,,0),(t_("Eq"),15-5,,5.2-5,,10):}`
`:. K_(c )=([HI]^(2))/([H_(2)][I_(2)])=100/(10xx0.2)=50`