The kinetic energy of `4 mol` of nitrogen gas at `127^(@) C` is …….. `cal(R = 2 cal mol^(-1) K^(-1))`

Correct Answer - C
According to the kinetic molecular theory , kinetic energy `(KE)` for `n` moles is given as
`KE = (3)/(2) nRT`
`= (3)/(2) (4 "mol") (2 "cal mol"^(-1) K^(-1)) (400 K)`
`= 4800 cal`

The kinetic energy of `4 mol` of nitrogen gas at `127^(@) C` is …….. `cal(R = 2 cal mol^(-1) K^(-1))`

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