Question

A bulb A containing gas at 1.5 bar pressure was connected to an evacuated vessel of 1.0 `dm^(3)` capacity through a stopcock. The final pressure of the system dropped to 920 mbar at the same temperature. What is the volume of the container A?

Answer 1

`V_(1)=1.0dm^(3)`
`V_(2)=(1.0+V)dm^(3)`
`P_(1)=1.5` bar
`P_(2)=920` mbar`=0.92` bar
Apply `P_(1)V_(1)=P_(2)V_(2)`
`(1.5)(1.0)=(1.0+V)(0.92`bar)
`1.5=0.92+0.92V`
or `0.92=1.5-0.92=0.58`
`thereforeV=0.58//0.92=0.6304dm^(3)`