Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
558 views
in Chemistry by (63.2k points)
closed by
A large flask fitted with a stopcock is evacuated and weighted. Its mass is found to be 134.567 g. It is then filled at a pressure of 735 mm and `131^(@)C` with a gas of unknown molecular mass and then reweighed. Its mass is 137.456 g. The flask is then rewighed. Its mass weighted again, its mass is now 1067.9 g. Assuming that the gas is ideal, calculate the molar mass of the gas.

1 Answer

0 votes
by (67.2k points)
selected by
 
Best answer
Mass of water filling the flask is
`(10.67.9-134.567)g=933.333g`
`therefore` volume of flask=volume of water filling the flask ltbr `=933.3cm^(3)`
`(therefore` density of `H_(2)O=1gcm^(-3)`)
Now `P=735mm`, `T=31+273K=304K`
`V=933.3cm^(3)`
applying `PV=nRT`
`((735)/(760)atm)((933.3)/(1000)L)=nxx0.0821xx304`
gives `n=0.036mo`
Mass of 0.036 mol of the gas `=(137.456-134.567)g`
`=2.889g`
therefore mass of 1 mol of the gas `=(2.889)/(0.036)=80.25g` `mol^(-1)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...