Question

0.3 g of platinichloride of an organic diacidic base left 0.09 g of platinum on ignition. The molecular weight of the organic base is
A. 120
B. 240
C. 180
D. 60

Answer 1

Correct Answer - B
Let B is the original bese.
`2B+H_2(2)PtCl_(6)toB_(2)H_(2)PtCl_(2)overset(Delta)toPt`
Ew of `B_(2)H_(2)PtCl_(2)=2B+2+195+6xx35.5`
`=2B+410`
`("Weight of chlorophatinate")/("Weight of" Pt)=("Ew of salt")/(Ew of Pt)`
`(0.3)/(0.09)=(2B+410)/(195)`
`B(Ew of base)=120`
Mw of `base=Ewxxacidity`
`=120xx2=240`