Question

If the law of constant compositon is true, what weights of calcium carbon, and oxygen are present in `1.5 g` of calcium carbonate, if a sample of calcium carbonate from another source contains the following percentage composition: `Ca = 40.0%, C = 12.0%`, and `O = 48.0%`?

Answer 1

Correct Answer - A::B::C
According to the law, the samples, of calcium carbonate from the sources must be identical, i.e., their percentage composition must be the same.
Thus, the weight, `Ca, C`, and `O` in `1.5 g CaCO_(3)` are:
Calcium `(Ca) = (40 xx 1.5)/(100) = 0.60 g`
Carbon `(C ) = (12 xx 1.5)/(100) = 0.18 g,`
Oxygen `(O) = (48 xx 1.5)/(100) = 0.72 g`