Correct Answer - C
Balance of equation:
Given : `underset({:(1 "mmol"),(50 xx 0.1),(= 5 "mmol"):})(BrCO_(3)^(ɵ)) + underset({:(5 "mmol"),(30 xx 0.5),(= 15 "mmol"):})(5Br^(ɵ)) rarr underset(1 "mmol")(3Br_(2)) + 3H_(2) O`
`Br^(ɵ)` is the limiting reagent.
5 mmol of `Br^(ɵ)` gives `implies` 3 mmol of `Br_(2)`
15 mmol of `Br^(ɵ)` gives `implies (3 xx 15)/(5) = 9 "mmo"`
`9 xx 10^(-3) "mol"`