Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
101 views
in Chemistry by (73.8k points)
closed by
The rapid change of pH near the stocichiometric point of an acid-base titration is the basis of indicator detrection. pH of the solution is related to the ratio of concentration of conjugate acid (HIn) to the concentration of base `(In^(-))` froms of the indicator by the expression
A. `"log"([In^(-)])/([HIn])=pK_(In)-pH`
B. `"log"([HIn])/([In^(-)])=pK_(In)-pH`
C. `"log"([HIn])/([In^(-)])=pH-pK_(In)`
D. `"log"([In^(-)])/([HIn])=pH-pK_(In)`

1 Answer

0 votes
by (74.1k points)
selected by
 
Best answer
Correct Answer - D
Consider the equilibrium expression
`HIn hArr H^(+)+In^(-)`
`K_(In)=([H^(+)][In^(-)])/([HIn])=[H^(+)] ([In^(-)])/([HIn])`
Taking negative log of both sides, we have
`-log K_(In)= -log[H^(+)]- log.([In^(-)])/([H In])`
`pK_(In)=pH-log. ([In^(-)])/([H In])`
or `log. ([In^(-)])/([H In]) = pH-pK_(In)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...