Question

A solution has been prepared by dissolving 0.063 g of `HNO_(3)` in 1000 mL of It . Calculate the `[H^(+)]` and `[OH^(-)]` of the solution.

Answer 1

Molar concetration of `HNO_(3) = ("Mass of" HNO_(3) // "litre of solution")/("Molar mass of"HNO_(3)) = ((0.063g))/((63g" mol "^(-1))`
`=1.0xx 10^(-3)M`
`HNO_(3)` is a strong acid and is ompletely ionised in water.
`{:(HNO_(3),overset(aq)(to),Na^(+) (aq),+, OH^(-)(aq)),(,,1.0xx10^(-3)M,,1.0xx10^(-3)M):}`
`:." "[H_(3)O^(+)] = [HNO_(3)] = 1.0 xx 10^(-3)M`
`"["OH^(-)"]"=(K_(w))/[[H_(3)O^(+)]]=((1.0xx10^(-14)M^(2)))/((1.0xx10^(-3)M)) = 10^(-11)M`