Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
107 views
in Chemistry by (74.1k points)
closed by
Arrange the following molecules in increasing order of intermolecular forces : `C_(2)H_(6),CH_(3)NH_(2),CH_(3)F` and `CH_(2)F_(2)`

1 Answer

0 votes
by (73.7k points)
selected by
 
Best answer
Greater the intermolecular forces, greater is the boiling point.
`C_(2)H_(6)` has only London forces,`CH_(3)NH_(2)` has hydrogen bonding and London forces. `CH_(3)F` and `CH_(2)F_(2)` have dipole-dipole attractions besides London forces, but dipole-dipole attractions in `CH_(2)F_(2)` are greater than those in `CH_(3)F`. Hence, order of boiling point is `C_(2)H_(6)(-88^(@)C)ltCH_(3)F(-78^(@)C)ltCH_(2)F_(2)(-52^(@)C)ltCH_(3)NH_(2)(-6^(@C)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...