Question

A 10.0 litre container is filled with a gas to a pressure of 2.00 atm at `0^(@)C`. At what temperature will the pressure inside the container be 2.50 atm ?

Answer 1

As volume of the container remains constant, applying pressure-temperature law, viz., ,
`(P_(1))/(T_(1))=(P_(2))/(T_(2))`, we get `(2 atm)/(273 K)=(2.50 atm)/(T_(2))" or " T_(2)=341 K=341-273^(@)C=68^(@)C`