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By what factor does the average velocity of a gaseous molecule increase when the absolute temperature is doubled ?

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By what factor does the average velocity of a gaseous molecule increase when the absolute temperature is doubled ?
A. 1.4
B. `2.0`
C. `2.8`
D. `4.0`
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Correct Answer - A
Average velocity `(vecc)=sqrt((8RT)/(piM))`
If absolute temperature is doubled, new average velocity `=sqrt((8R.2T)/(piM))=sqrt(2)bar(c )=1.4bar(c )`
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