Question

How the bond energey varies from `N_(2)^(Θ)` and `N_(2)^(o+)` and why ?
(b) On the basic of molecular orbital theory what is the similarity between
(i) `F_(2)` and `O_(2)^(2-)` (ii) `CO,N_(2)` and `NO^(o+)` ? .

Answer 1

Bond energy of `N_(2)^(o+)` = Bond energy of `N_(2)^(Θ)` because the bond order is same in both the species. [Howerver `N_(2)^(o+)` is slightly more stable than `N_(2)^(Θ)` as number of antibonding electrons is higher in `N_(2)^(Θ)` than `N_(2)^(o+)`]
(b) Both `F_(2)` and `O_(2)^ (2-)` have same bond order, same bond lenght and red diamagmagnetic
(ii) These are isoelectronic species, possess same bond order and same bond lenght .